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TC2574-3.3VPA Datasheet(PDF) 9 Page - TelCom Semiconductor, Inc |
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TC2574-3.3VPA Datasheet(HTML) 9 Page - TelCom Semiconductor, Inc |
9 / 25 page 9 TC2574 0.5A Step-Down Switching Regulator TC2574-1 1/6/00 Procedure (Adjustable Output Version): (TC2574-ADJ) (Continued) Procedure Example 3. Catch Diode Selection (D1) A. Since the diode maximum peak current exceeds the regulator maximum load current the catch diode current rating must be at least 1.2 times greater than the maximum load current. For a robust design, the diode should have a current rating equal to the maximum current limit of the TC2574 to be able to with stand a continuous output short. B. The reverse voltage rating of the diode should be at least 1.25 times the maximum input voltage. 4. Inductor Selection (L1) A. Use the following formula to calculate the inductor Volt x microsecond [V x µs] constant: E x T = ( VIN – VOUT) VOUT x 10 6 [V x µsec] VIN F[Hz] B. Match the calculated E x T value with the corresponding number on the vertical axis of the Inductor Value Selection Guide shown in Figure 39. This E x T constant is a measure of the energy handling capability of an inductor and is dependent upon the type of core, the core area, the number of turns, and the duty cycle. C. Next step is to identify the inductance region intersected by the E x T value and the maximum load current value on the horizontal axis shown in Figure 8. D. From the inductor code, identify the inductor value. Then select an appropriate inductor from Table 2. The inductor chosen must be rated for a switching frequency of 52kHz and for a current rating of 1.15 x ILOAD . The inductor current rating can also be determined by calculating the inductor peak current: IP (max) = ILOAD(max) + (VIN – VOUT) tON 2L where tON is the "on" time of the power switch and tON = (VOUT x 1.0 ) VIN fOSC For additional information about the inductor, see the inductor section in the “EXTERNAL COMPONENTS” section of this data sheet. 3. Catch Diode Selection (D1) A. For this example, a 1.0A current rating is adequate. B. Use a 50V MBR150 Schottky diode or any suggested fast recovery diodes in Table 1. 4. Inductor Selection (L1) A. Calculate E x T [V x µsec] constant: E x T = (40 – 24) x 24 x 1000 = 105[V x µsec] 40 52 B. E x T = 185 [V x µsec] C. ILOAD(max) = 0.4 A Inductance Region = 1000 D. Proper inductor value = 1000 µH Choose the inductor from Table 2. |
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