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LM2734Z Datasheet(PDF) 8 Page - Texas Instruments

No. de pieza LM2734Z
Descripción Electrónicos  LM2734Z/LM2734ZQ Thin SOT 1A Load Step-Down DC-DC Regulator
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Fabricante Electrónico  TI [Texas Instruments]
Página de inicio  http://www.ti.com
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LM2734Z Datasheet(HTML) 8 Page - Texas Instruments

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LM2734
VIN
BOOST
SW
GND
CBOOST
L
D1
D2
D3
CIN
VIN
COUT
VOUT
VBOOST
LM2734Z
SNVS334E – JANUARY 2005 – REVISED APRIL 2013
www.ti.com
In the Simplifed Block Diagram of Block Diagram, capacitor CBOOST and diode D2 supply the gate-drive current
for the NMOS switch. Capacitor CBOOST is charged via diode D2 by VIN. During a normal switching cycle, when
the internal NMOS control switch is off (TOFF) (refer to Figure 9), VBOOST equals VIN minus the forward voltage of
D2 (VFD2), during which the current in the inductor (L) forward biases the Schottky diode D1 (VFD1). Therefore the
voltage stored across CBOOST is
VBOOST - VSW = VIN - VFD2 + VFD1
(1)
When the NMOS switch turns on (TON), the switch pin rises to
VSW = VIN – (RDSON x IL),
(2)
forcing VBOOST to rise thus reverse biasing D2. The voltage at VBOOST is then
VBOOST = 2VIN – (RDSON x IL) – VFD2 + VFD1
(3)
which is approximately
2VIN - 0.4V
(4)
for many applications. Thus the gate-drive voltage of the NMOS switch is approximately
VIN - 0.2V
(5)
An alternate method for charging CBOOST is to connect D2 to the output as shown in Figure 10. The output
voltage should be between 2.5V and 5.5V, so that proper gate voltage will be applied to the internal switch. In
this circuit, CBOOST provides a gate drive voltage that is slightly less than VOUT.
In applications where both VIN and VOUT are greater than 5.5V, or less than 3V, CBOOST cannot be charged
directly from these voltages. If VIN and VOUT are greater than 5.5V, CBOOST can be charged from VIN or VOUT
minus a zener voltage by placing a zener diode D3 in series with D2, as shown in Figure 11. When using a
series zener diode from the input, ensure that the regulation of the input supply doesn’t create a voltage that falls
outside the recommended VBOOST voltage.
(VINMAX – VD3) < 5.5V
(6)
(VINMIN – VD3) > 1.6V
(7)
Figure 11. Zener Reduces Boost Voltage from VIN
An alternative method is to place the zener diode D3 in a shunt configuration as shown in Figure 12. A small
350mW to 500mW 5.1V zener in a SOT or SOD package can be used for this purpose. A small ceramic
capacitor such as a 6.3V, 0.1µF capacitor (C4) should be placed in parallel with the zener diode. When the
internal NMOS switch turns on, a pulse of current is drawn to charge the internal NMOS gate capacitance. The
0.1 µF parallel shunt capacitor ensures that the VBOOST voltage is maintained during this time.
Resistor R3 should be chosen to provide enough RMS current to the zener diode (D3) and to the BOOST pin. A
recommended choice for the zener current (IZENER) is 1 mA. The current IBOOST into the BOOST pin supplies the
gate current of the NMOS control switch and varies typically according to the following formula:
IBOOST = (D + 0.5) x (VZENER – VD2) mA
(8)
where D is the duty cycle, VZENER and VD2 are in volts, and IBOOST is in milliamps. VZENER is the voltage applied to
the anode of the boost diode (D2), and VD2 is the average forward voltage across D2. Note that this formula for
IBOOST gives typical current. For the worst case IBOOST, increase the current by 25%. In that case, the worst case
boost current will be
IBOOST-MAX = 1.25 x IBOOST
(9)
8
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