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BCM48BF040T200B00 Datasheet(PDF) 11 Page - Vicor Corporation |
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BCM48BF040T200B00 Datasheet(HTML) 11 Page - Vicor Corporation |
11 / 18 page BCM® Bus Converter Rev 1.2 vicorpower.com Page 11 of 18 07/2015 800 927.9474 x040 200 y B 48 BCM B00 9.0 SINE AMPLITUDE CONVERTER™ POINT OF LOAD CONVERSION The Sine Amplitude Converter (SAC™) uses a high frequency resonant tank to move energy from input to output. (The resonant tank is formed by Cr and leakage inductance Lr in the power transformer windings as shown in the BCM module Block Diagram. See Section 8). The resonant LC tank, operated at high frequency, is amplitude modulated as a function of input voltage and output current. A small amount of capacitance embedded in the input and output stages of the module is sufficient for full functionality and is key to achieving power density. The BCM48BF040T200B00 SAC can be simplified into the preceeding model. At no load: VOUT = VIN • K (1) K represents the “turns ratio” of the SAC. Rearranging Eq (1): K= VOUT (2) VIN In the presence of load, VOUT is represented by: VOUT = VIN • K – IOUT • ROUT (3) and IOUT is represented by: IOUT = IIN –IQ (4) K ROUT represents the impedance of the SAC, and is a function of the RDSON of the input and output MOSFETs and the winding resistance of the power transformer. IQ represents the quiescent current of the SAC control, gate drive circuitry, and core losses. The use of DC voltage transformation provides additional interesting attributes. Assuming that ROUT = 0 Ω and IQ = 0 A, Eq. (3) now becomes Eq. (1) and is essentially load independent, resistor R is now placed in series with VIN. The relationship between VIN and VOUT becomes: VOUT = (VIN –IIN • R) • K (5) Substituting the simplified version of Eq. (4) (IQ is assumed = 0 A) into Eq. (5) yields: VOUT = VIN • K – IOUT • R • K2 (6) + – + – VOUT COUT VIN V•I K + – + – CIN IOUT RCOUT IQ ROUT RCIN 100 mA 1/12 • IOUT 1/12 • VIN 2.4 m Ω RCIN 0.57 m Ω 286 pH 0.35 Ω RCOUT 130 µ Ω 200 µF LOUT = 600 pH 2 µF IQ LIN = 5.7 nH IOUT ROUT VIN VOUT R SAC K = 1/32 Vin Vout + – VIN VOUT R SAC™ K = 1/12 Figure 14 — K = 1/12 Sine Amplitude Converter™ with series input resistor Figure 13 — VI Chip ® module AC model COUT CIN |
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